Thursday, April 21, 2011

How to create object from String?

I tried the code below:

$dyn = "new ". $className . "(" .$param1 . ", ". $param2 . ");";
$obj = eval($dyn);

It compiles but it's null.

How can you instance object in PHP dynamicaly?

From stackoverflow
  • $class = 'ClassName';
    $obj = new $class($arg1, $arg2);
    
  • If you really want to use eval - which chances are you shouldn't if you're this new to PHP ;) - you'd do something more like...

    $dyn = "new ". $className . "(" .$param1 . ", ". $param2 . ");";
    eval("\$obj = $dyn");
    
  • What are you actually trying to accomplish? eval would work, but its probably not a very good idea.

    What you might want to do is implement a factory for your objects that take a string defining what class to load, and an optional array for the constructors parameters

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