Hi all,
#/!bin/sh
if [ "`echo $desc $status | awk -F"," '{print $3}' | awk -F" " '{print $1}' | sed '/^$/d'`" != "OK" ]; then
echo "howdy dody"
fi
echo $desc $status | awk -F"," '{print $3}' | awk -F" " '{print $1}' | sed '/^$/d'
First if-condition won't run, im guessing it's because of improper quotation, but i can't figure it out.
Thanks in advance for any help.
-
If you're using Bash, I'd recommend
$(...)
instead of back-quotes. What error messages do you get? My guess is that the-F","
option to awk is not being quoted properly. Trying inserting\
to escape the quotation marks.Anders : Sorry, can't use $(...) very very old shell. MMm, good suggestion, gonna try that.ghostdog74 : can't use $()?? then why the bash tag?Anders : Changed the topic.Anders : Was simply a matter of escaping. Thanks for the help.JesperE : Update the tags as well, please.Anders : Done, thanks for the help. -
At first glance, you might want to try escaping some of the double quotes:
if [ "`echo $desc $status | awk -F"," '{print $3}' | awk -F" " '{print $1}' | sed '/^$/d'`" != "OK" ]; then echo "howdy dody" fi
to
if [ "`echo $desc $status | awk -F\",\" '{print $3}' | awk -F\" \" '{print $1}' | sed '/^$/d'`" != "OK" ]; then echo "howdy doody" fi
Anders : Thanks for the help. -
You can also use single quotes around the argument to the
-F
option as you have around other arguments:if [ "`echo $desc $status | awk -F',' '{print $3}' | awk -F' ' '{print $1}' | sed '/^$/d'`" != "OK" ]; then
-
Escaping the double quotes is certainly a good idea, but it looks like the $3 and the $1 are intended to be interpreted by awk. They are being interpreted by your shell instead. You probably want to escape the '$'s. (It is possible that you have meaningful values for $1 and $3 in the shell, but not likely.)
Dennis Williamson : No, they're in single quotes so they don't need escaping.
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