How to obtain the sign of a Number in ActionScript 3.0?

I have a variable of type Number, and i like to obtain the sign (if is '-' i like to have -1 and if '+' i like to have 1). So, i made this:

var sign = Math.abs(n) / n;

But, there is any other way? Better than this?

From stackoverflow unkiwii

• You'll be in trouble if n == 0... how about this:

  var sign = n < 0 ? -1 : 1;
  

  davr : dang, beat me by 15 seconds :P

  unkiwii : thanks, jaja.. i didn't think about n==0. :P

  matt lohkamp : this is a beautiful little piece of code.
  From bobwienholt

• You could also do this:

  var sign = (n>=0)?1:-1;
  

  Using what's known as the ternary operator.

  From davr

• That will give you an error if n is zero.

  The brute force method:

  function sign(num) {
    if(num > 0) {
      return 1;
    } else if(num < 0) {
      return -1;
    } else {
      return 0;
    }
  }
  

  Or, for those with a fondness for the conditional operator:

  function sign(num) {
    return (num > 0) ? 1 : ((num < 0) ? -1 : 0);
  }
  

  DL Redden : I like the second approach, it's much cleaner and it deals with the possibility of n being 0.

  unkiwii : the sign of 0 is + not 0, so: return (num < 0) ? -1 : 1; Thanks for your answer
  From Glomek

• If your number fits in 31 bits then you can use:

  var sign = 1 + 2*(n >> 31);
  

  Would be interesting to know if this is any faster!

  From $pageUsers[$post.author].name

• Snippet from the code I inherited:

  function getSign(number:int):int {
      var tmp:String = new String(number);
      if (tmp.indexOf(0) == '-') {
          return -1;
      }
      return 1;
  }
  

  PS: Please don't use this code. It is a joke

  From Chetan Sastry